A thin circular ring of mass M and radius r is rotating about its axis with an angular speed $\omega$. Two particles having mass m each are now attached at diametrically opposite points. The angular speed of the ring will become :
$\omega {M \over {M + m}}$
$\omega {{M + 2m} \over M}$
$\omega {M \over {M + 2m}}$
$\omega {{M - 2m} \over {M + 2m}}$
Solution
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