The time period of a simple pendulum is given by $T = 2\pi \sqrt {{l \over g}} $. The measured value of the length of pendulum is 10 cm known to a 1mm accuracy. The time for 200 oscillations of the pendulum is found to be 100 second using a clock of 1s resolution. The percentage accuracy in the determination of 'g' using this pendulum is 'x'. The value of 'x' to be nearest integer is :-
2%
3%
5%
4%
Solution
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