The value of the limit $\mathop {\lim }\limits_{\theta \to 0} {{\tan (\pi {{\cos }^2}\theta )} \over {\sin (2\pi {{\sin }^2}\theta )}}$ is equal to :

Question

The value of the limit

$\mathop {\lim }\limits_{\theta \to 0} {{\tan (\pi {{\cos }^2}\theta )} \over {\sin (2\pi {{\sin }^2}\theta )}}$ is equal to :

$-$${1 \over 2}$

${1 \over 4}$

$-$${1 \over 4}$

Solution

Please login to view the detailed solution steps...

Go to DASH