An electron of mass m and a photon have same energy E. The ratio of wavelength of electron to that of photon is : (c being the velocity of light)

Question

${1 \over c}{\left( {{{2m} \over E}} \right)^{1/2}}$

${1 \over c}{\left( {{E \over {2m}}} \right)^{1/2}}$

${\left( {{E \over {2m}}} \right)^{1/2}}$

$c{(2mE)^{1/2}}$

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