Your AI-Powered Personal Tutor
Question
For the reaction $A(g) \rightleftharpoons B(g)$ at 495 K, $\Delta$rG$^\circ$ = $-$9.478 kJ mol$-$1.
If we start the reaction in a closed container at 495 K with 22 millimoles of A, the amount of B in the equilibrium mixture is ____________ millimoles.
(Round off to the Nearest Integer). [R = 8.314 J mol$-$1 K$-$1; ln 10 = 2.303]
Correct Answer
20

Solution

Please login to view the detailed solution steps...

Go to DASH