For changing the capacitance of a given parallel plate capacitor, a dielectric material of dielectric constant K is used, which has the same area as the plates of the capacitor. The thickness of the dielectric slab is ${3 \over 4}$d, where 'd' is the separation between the plates of parallel plate capacitor. The new capacitance (C') in terms of original capacitance (C0) is given by the following relation :

Question

For changing the capacitance of a given parallel plate capacitor, a dielectric material of dielectric constant K is used, which has the same area as the plates of the capacitor. The thickness of the dielectric slab is ${3 \over 4}$d, where 'd' is the separation between the plates of parallel plate capacitor. The new capacitance (C') in terms of original capacitance (C₀) is given by the following relation :

$C' = {{3 + K} \over {4K}}{C_0}$

$C' = {{4 + K} \over {3}}{C_0}$

$C' = {{4K} \over {K + 3}}{C_0}$

$C' = {{4} \over {3 + K}}{C_0}$

Solution

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