One main scale division of a vernier callipers is 'a' cm and nth division of the vernier scale coincide with (n $-$ 1)th division of the main scale. The least count of the callipers in mm is :

Question

One main scale division of a vernier callipers is 'a' cm and n^th division of the vernier scale coincide with (n $-$ 1)^th division of the main scale. The least count of the callipers in mm is :

${{10a} \over n}$

${{10na} \over {(n - 1)}}$

$\left( {{{n - 1} \over {10n}}} \right)a$

${{10a} \over {(n - 1)}}$

Solution

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