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Question
Emf of the following cell at 298K in V is x $\times$ 10$-$2.

Zn|Zn2+(0.1 M)||Ag+ (0.01 M)|Ag

The value of x is _________. (Rounded off to the nearest integer)

[Given : $E_{Z{n^{2 + }}/Zn}^\theta = - 0.76V;E_{A{g^{2 + }}/Ag}^\theta = + 0.80V;{{2.303RT} \over F} = 0.059$]
Correct Answer
147

Solution

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