Let R = {(P, Q) | P and Q are at the same distance from the origin} be a relation, then the equivalence class of (1, $-$1) is the set :

Question

$S = \{ (x,y)|{x^2} + {y^2} = \sqrt 2 \} $

$S = \{ (x,y)|{x^2} + {y^2} = 2\} $

$S = \{ (x,y)|{x^2} + {y^2} = 1\} $

$S = \{ (x,y)|{x^2} + {y^2} = 4\} $

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