A large number of water drops, each of radius r, combine to have a drop of radius R. If the surface tension is T and mechanical equivalent of heat is J, the rise in heat energy per unit volume will be :

Question

${{2T} \over J}\left( {{1 \over r} - {1 \over R}} \right)$

${{3T} \over J}\left( {{1 \over r} - {1 \over R}} \right)$

${{3T} \over rJ}$

${{2T} \over rJ}$

Solution

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