If 0 < x, y < $\pi$ and cosx + cosy $-$ cos(x + y) = ${3 \over 2}$, then sinx + cosy is equal to :

Question

${{1 + \sqrt 3 } \over 2}$

${{1 \over 2}}$

${{\sqrt 3 } \over 2}$

${{1 - \sqrt 3 } \over 2}$

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