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Question
The value of $\int\limits_{ - 1}^1 {{x^2}{e^{[{x^3}]}}} dx$, where [ t ] denotes the greatest integer $ \le $ t, is :
${{e + 1} \over 3}$
${{e - 1} \over {3e}}$
${1 \over {3e}}$
${{e + 1} \over {3e}}$

Solution

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