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Question
The image of the point (3, 5) in the line x $-$ y + 1 = 0, lies on :
(x $-$ 4)2 + (y $-$ 4)2 = 8
(x $-$ 4)2 + (y $+$ 2)2 = 16
(x $-$ 2)2 + (y $-$ 2)2 = 12
(x $-$ 2)2 + (y $-$ 4)2 = 4

Solution

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