The solubility product of PbI₂ is 8.0 $\times$ 10^$-$9. The solubility of lead iodide in 0.1 molar solution of lead nitrate is x $\times$ 10^$-$6. mol/L. The value of x is __________. (Rounded off to the nearest integer) [Given $\sqrt 2 $ = 1.41]