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Question
The area (in sq. units) of the part of the circle x2 + y2 = 36, which is outside the parabola y2 = 9x, is :
$12\pi - 3\sqrt 3 $
$24\pi + 3\sqrt 3 $
$24\pi - 3\sqrt 3 $
$12\pi + 3\sqrt 3 $

Solution

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