Question
The probabilities of three events A, B and C are
given by
P(A) = 0.6, P(B) = 0.4 and P(C) = 0.5.
If P(A$ \cup $B) = 0.8, P(A$ \cap $C) = 0.3, P(A$ \cap $B$ \cap $C) = 0.2, P(B$ \cap $C) = $\beta $
and P(A$ \cup $B$ \cup $C) = $\alpha $, where 0.85 $ \le \alpha \le $ 0.95, then $\beta $ lies in the interval :
P(A) = 0.6, P(B) = 0.4 and P(C) = 0.5.
If P(A$ \cup $B) = 0.8, P(A$ \cap $C) = 0.3, P(A$ \cap $B$ \cap $C) = 0.2, P(B$ \cap $C) = $\beta $
and P(A$ \cup $B$ \cup $C) = $\alpha $, where 0.85 $ \le \alpha \le $ 0.95, then $\beta $ lies in the interval :