A charged particle going around in a circle can be considered to be a current loop. A particle of
mass m carrying charge q is moving in a plane with speed v under the influence of magnetic field $\overrightarrow B $.
The magnetic moment of this moving particle:
${{m{v^2}\overrightarrow B } \over {2{B^2}}}$
-${{m{v^2}\overrightarrow B } \over {2{B^2}}}$
-${{m{v^2}\overrightarrow B } \over {{B^2}}}$
-${{m{v^2}\overrightarrow B } \over {2\pi {B^2}}}$
Solution
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