Given the masses of various atomic particles mp = 1.0072 u, mn = 1.0087 u, me = 0.000548 u, ${m_{\overline v }}$ = 0, md = 2.0141 u, where p $ \equiv $ proton, n $ \equiv $ neutron, e $ \equiv $ electron, $\overline v $ $ \equiv $ antineutrino and d $ \equiv $ deuteron. Which of the following process is allowed by momentum and energy conservation?

Question

Given the masses of various atomic particles
m_p = 1.0072 u, m_n = 1.0087 u, m_e = 0.000548 u,
${m_{\overline v }}$ = 0, m_d = 2.0141 u, where p $ \equiv $ proton, n $ \equiv $ neutron,
e $ \equiv $ electron, $\overline v $ $ \equiv $ antineutrino and d $ \equiv $ deuteron. Which of the following process is allowed by momentum and energy conservation?

n + n $ \to $ deuterium atom
(electron bound to the nucleus)

n + p $ \to $ d + $\gamma $

p $ \to $ n + e⁺ + $\overline v $

e⁺ + e^- $ \to $ $\gamma $

Solution

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