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Question
$\mathop {\lim }\limits_{x \to 1} \left( {{{\int\limits_0^{{{\left( {x - 1} \right)}^2}} {t\cos \left( {{t^2}} \right)dt} } \over {\left( {x - 1} \right)\sin \left( {x - 1} \right)}}} \right)$
is equal to 0
is equal to ${1 \over 2}$
does not exist
is equal to $ - {1 \over 2}$

Solution

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