If $\alpha $ and $\beta $ be two roots of the equation x2 – 64x + 256 = 0. Then the value of ${\left( {{{{\alpha ^3}} \over {{\beta ^5}}}} \right)^{1/8}} + {\left( {{{{\beta ^3}} \over {{\alpha ^5}}}} \right)^{1/8}}$ is :

Question

If $\alpha $ and $\beta $ be two roots of the equation
x² – 64x + 256 = 0. Then the value of
${\left( {{{{\alpha ^3}} \over {{\beta ^5}}}} \right)^{1/8}} + {\left( {{{{\beta ^3}} \over {{\alpha ^5}}}} \right)^{1/8}}$ is :

Solution

Please login to view the detailed solution steps...

Go to DASH