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Question
If I1 = $\int\limits_0^1 {{{\left( {1 - {x^{50}}} \right)}^{100}}} dx$ and
I2 = $\int\limits_0^1 {{{\left( {1 - {x^{50}}} \right)}^{101}}} dx$ such
that I2 = $\alpha $I1 then $\alpha $ equals to :
${{5051} \over {5050}}$
${{5050} \over {5051}}$
${{5050} \over {5049}}$
${{5049} \over {5050}}$

Solution

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