An electron, a doubly ionized helium ion (He++) and a proton are having the same kinetic energy. The relation between their respective de-Broglie wavelengths $\lambda $e, $\lambda $He++ and $\lambda $p is :

Question

An electron, a doubly ionized helium ion (He⁺⁺) and a proton are having the same kinetic energy. The relation between their respective de-Broglie wavelengths $\lambda $_e, $\lambda $_He⁺⁺ and $\lambda $_p is :

$\lambda $_e > $\lambda $_He⁺⁺ > $\lambda $_p

$\lambda $_e < $\lambda $_p < $\lambda $_He⁺⁺

$\lambda $_e > $\lambda $_p > $\lambda $_He⁺⁺

$\lambda $_e < $\lambda $_He⁺⁺ = $\lambda $_p

Solution

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