Charges Q1 and Q2 are at points A and B of a right angle triangle OAB (see figure). The resultant electric field at point O is perpendicular to the hypotenuse, then ${{{Q_1}} \over {{Q_2}}}$ is proportional to :

Question

Charges Q₁ and Q₂ are at points A and B of a right angle triangle OAB (see figure). The resultant electric field at point O is perpendicular to the hypotenuse, then
${{{Q_1}} \over {{Q_2}}}$ is proportional to :

${{x_1^3} \over {x_2^3}}$

${{x_2^2} \over {x_1^2}}$

${{{x_1}} \over {{x_2}}}$

${{{x_2}} \over {{x_1}}}$

Solution

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