If L = sin2$\left( {{\pi \over {16}}} \right)$ - sin2$\left( {{\pi \over {8}}} \right)$ and M = cos2$\left( {{\pi \over {16}}} \right)$ - sin2$\left( {{\pi \over {8}}} \right)$, then :

Question

If L = sin²$\left( {{\pi \over {16}}} \right)$ - sin²$\left( {{\pi \over {8}}} \right)$ and
M = cos²$\left( {{\pi \over {16}}} \right)$ - sin²$\left( {{\pi \over {8}}} \right)$, then :

L = $ - {1 \over {2\sqrt 2 }} + {1 \over 2}\cos {\pi \over 8}$

M = ${1 \over {2\sqrt 2 }} + {1 \over 2}\cos {\pi \over 8}$

M = ${1 \over {4\sqrt 2 }} + {1 \over 4}\cos {\pi \over 8}$

L = ${1 \over {4\sqrt 2 }} - {1 \over 4}\cos {\pi \over 8}$

Solution

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