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Question
Ten charges are placed on the circumference of a circle of radius R with constant angular separation between successive charges. Alternate charges 1, 3, 5, 7, 9 have charge (+q) each, while 2, 4, 6, 8, 10 have charge (–q) each. The potential V and the electric field E at the centre of the circle are respectively.
(Take V = 0 at infinity)
V = 0; E = 0
$V = {{10q} \over {4\pi {\varepsilon _0}R}}$; $E = {{10q} \over {4\pi {\varepsilon _0}{R^2}}}$
$V = {{10q} \over {4\pi {\varepsilon _0}R}}$; E = 0
V = 0; $E = {{10q} \over {4\pi {\varepsilon _0}{R^2}}}$

Solution

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