If y = y(x) is the solution of the differential equation ${{5 + {e^x}} \over {2 + y}}.{{dy} \over {dx}} + {e^x} = 0$ satisfying y(0) = 1, then a value of y(loge13) is :

Question

If y = y(x) is the solution of the differential

equation ${{5 + {e^x}} \over {2 + y}}.{{dy} \over {dx}} + {e^x} = 0$ satisfying y(0) = 1, then a value of y(log_e13) is :

-1

Solution

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