If the function $$f\left( x \right) = \left\{ {\matrix{ {{k_1}{{\left( {x - \pi } \right)}^2} - 1,} & {x \le \pi } \cr {{k_2}\cos x,} & {x > \pi } \cr } } \right.$$ is twice differentiable, then the ordered pair (k1, k2) is equal to :

Question

If the function
$$f\left( x \right) = \left\{ {\matrix{ {{k_1}{{\left( {x - \pi } \right)}^2} - 1,} & {x \le \pi } \cr {{k_2}\cos x,} & {x > \pi } \cr } } \right.$$ is
twice differentiable, then the ordered pair (k₁, k₂) is equal to :

$\left( {{1 \over 2},-1} \right)$

(1, 1)

(1, 0)

$\left( {{1 \over 2},1} \right)$

Solution

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