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Question
If
$\int {\left( {{e^{2x}} + 2{e^x} - {e^{ - x}} - 1} \right){e^{\left( {{e^x} + {e^{ - x}}} \right)}}dx} $ = $g\left( x \right){e^{\left( {{e^x} + {e^{ - x}}} \right)}} + c$

where c is a constant of integration, then g(0) is equal to :
1
2
e
e2

Solution

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