The value of the acceleration due to gravity is g1 at a height h = ${R \over 2}$ (R = radius of the earth) from the surface of the earth. It is again equal to g1 at a depth d below the surface of the earth. The ratio $\left( {{d \over R}} \right)$ equals :

Question

The value of the acceleration due to gravity is g₁ at a height h = ${R \over 2}$ (R = radius of the earth) from the surface of the earth. It is again equal to g₁ at a depth d below the surface of the earth. The ratio $\left( {{d \over R}} \right)$ equals :

${5 \over 9}$

${1 \over 9}$

${7 \over 9}$

${4 \over 9}$

Solution

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