The shortest wavelength of H atom in the Lyman series is $\lambda $1. The longest wavelength in the Balmar series of He+ is :

Question

The shortest wavelength of H atom in the Lyman series is $\lambda $₁. The longest wavelength in the Balmar series of He⁺ is :

${{5{\lambda _1}} \over 9}$

${{36{\lambda _1}} \over 5}$

${{27{\lambda _1}} \over 5}$

${{9{\lambda _1}} \over 5}$

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