The solution of the differential equation ${{dy} \over {dx}} - {{y + 3x} \over {{{\log }_e}\left( {y + 3x} \right)}} + 3 = 0$ is: (where c is a constant of integration)

Question

The solution of the differential equation

${{dy} \over {dx}} - {{y + 3x} \over {{{\log }_e}\left( {y + 3x} \right)}} + 3 = 0$ is:

(where c is a constant of integration)

$x - {1 \over 2}{\left( {{{\log }_e}\left( {y + 3x} \right)} \right)^2} = C$

$y + 3x - {1 \over 2}{\left( {{{\log }_e}x} \right)^2} = C$

x – log_e(y+3x) = C

x – 2log_e(y+3x) = C

Solution

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