Let $\lambda \ne 0$ be in R. If $\alpha $ and $\beta $ are the roots of the equation, x2 - x + 2$\lambda $ = 0 and $\alpha $ and $\gamma $ are the roots of the equation, $3{x^2} - 10x + 27\lambda = 0$, then ${{\beta \gamma } \over \lambda }$ is equal to:

Question

Let $\lambda \ne 0$ be in R. If $\alpha $ and $\beta $ are the roots of the
equation, x² - x + 2$\lambda $ = 0 and $\alpha $ and $\gamma $ are the roots of
the equation, $3{x^2} - 10x + 27\lambda = 0$, then ${{\beta \gamma } \over \lambda }$ is equal to:

Solution

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