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Question
The integral $\int {{{\left( {{x \over {x\sin x + \cos x}}} \right)}^2}dx} $ is equal to
(where C is a constant of integration):
$\sec x - {{x\tan x} \over {x\sin x + \cos x}} + C$
$\sec x + {{x\tan x} \over {x\sin x + \cos x}} + C$
$\tan x - {{x\sec x} \over {x\sin x + \cos x}} + C$
$\tan x + {{x\sec x} \over {x\sin x + \cos x}} + C$

Solution

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