Let xi (1 $ \le $ i $ \le $ 10) be ten observations of a random variable X. If $\sum\limits_{i = 1}^{10} {\left( {{x_i} - p} \right)} = 3$ and $\sum\limits_{i = 1}^{10} {{{\left( {{x_i} - p} \right)}^2}} = 9$ where 0 $ \ne $ p $ \in $ R, then the standard deviation of these observations is :

Question

Let x_i (1 $ \le $ i $ \le $ 10) be ten observations of a random variable X. If
$\sum\limits_{i = 1}^{10} {\left( {{x_i} - p} \right)} = 3$ and $\sum\limits_{i = 1}^{10} {{{\left( {{x_i} - p} \right)}^2}} = 9$
where 0 $ \ne $ p $ \in $ R, then the standard deviation of these observations is :

${7 \over {10}}$

${9 \over {10}}$

${4 \over 5}$

$\sqrt {{3 \over 5}} $

Solution

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