If y2 + loge (cos2x) = y, $x \in \left( { - {\pi \over 2},{\pi \over 2}} \right)$, then :

Question

If y² + log_e (cos²x) = y,
$x \in \left( { - {\pi \over 2},{\pi \over 2}} \right)$, then :

|y''(0)| = 2

|y'(0)| + |y''(0)| = 3

y''(0) = 0

|y'(0)| + |y"(0)| = 1

Please login to view the detailed solution steps...