2$\pi $ - $\left( {{{\sin }^{ - 1}}{4 \over 5} + {{\sin }^{ - 1}}{5 \over {13}} + {{\sin }^{ - 1}}{{16} \over {65}}} \right)$ is equal to :

Question

${{7\pi } \over 4}$

${{5\pi } \over 4}$

${{3\pi } \over 2}$

${\pi \over 2}$

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