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Question

A block of mass m = 1 kg slides with velocity v = 6 m/s on a frictionless horizontal surface and collides with a uniform vertical rod and sticks to it as shown. The rod is pivoted about O and swings as a result of the collision making angle $\theta $ before momentarily coming to rest. If the rod has mass M = 2 kg, and length $l$ = 1 m, the value of $\theta $ is approximately :
(take g = 10 m/s2)

63o
69o
55o
49

Solution

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