Let f : (–1, $\infty $) $ \to $ R be defined by f(0) = 1 and f(x) = ${1 \over x}{\log _e}\left( {1 + x} \right)$, x $ \ne $ 0. Then the function f :

Question

Let f : (–1, $\infty $) $ \to $ R be defined by f(0) = 1 and
f(x) = ${1 \over x}{\log _e}\left( {1 + x} \right)$, x $ \ne $ 0. Then the function f :

decreases in (–1, $\infty $)

decreases in (–1, 0) and increases in (0, $\infty $)

increases in (–1, $\infty $)

increases in (–1, 0) and decreases in (0, $\infty $)

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