A random variable X has the following probability distribution : .tg {border-collapse:collapse;border-spacing:0;width:100%} .tg td{font-family:Arial, sans-serif;font-size:14px;padding:10px 5px;border-style:solid;border-width:1px;overflow:hidden;word-break:normal;border-color:black;} .tg th{font-family:Arial, sans-serif;font-size:14px;font-weight:normal;padding:10px 5px;border-style:solid;border-width:1px;overflow:hidden;word-break:normal;border-color:black;} .tg .tg-baqh{text-align:center;vertical-align:top} .tg .tg-wa1i{font-weight:bold;text-align:center;vertical-align:middle} .tg .tg-nrix{text-align:center;vertical-align:middle} X: 1 2 3 4 5 P(X): K2 2K K 2K 5K2 Then P(X > 2) is equal to :

Question

A random variable X has the following probability distribution :

X:	1	2	3	4	5
P(X):	K²	2K	K	2K	5K²

Then P(X > 2) is equal to :

${1 \over {6}}$

${7 \over {12}}$

${1 \over {36}}$

${23 \over {36}}$

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