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Question
If $x = \sum\limits_{n = 0}^\infty {{{\left( { - 1} \right)}^n}{{\tan }^{2n}}\theta } $ and $y = \sum\limits_{n = 0}^\infty {{{\cos }^{2n}}\theta } $

for 0 < $\theta $ < ${\pi \over 4}$, then :
x(1 + y) = 1
y(1 – x) = 1
y(1 + x) = 1
x(1 – y) = 1

Solution

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