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Question
If ${{dy} \over {dx}} = {{xy} \over {{x^2} + {y^2}}}$; y(1) = 1; then a value of x satisfying y(x) = e is :
$\sqrt 2 e$
${1 \over 2}\sqrt 3 e$
${e \over {\sqrt 2 }}$
$\sqrt 3 e$

Solution

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