The current i in the network is : - DASH

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Question

The current i in the network is :

0.6 A

0.3 A

0 A

0.2 A

Solution

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Step-by-Step Solution Step 1: Recognize the Role of the Diodes Observe that both diodes in the given circuit are reverse biased under the provided conditions. When a diode is reverse biased, it effectively acts as an open circuit (i.e., it does not conduct current). Step 2: Simplify the Circuit Since both diodes are open-circuited, remove them from the circuit. You then have only the resistors connected in series. These resistors are 5 Ω, 10 Ω, 5 Ω, and 10 Ω. Step 3: Calculate the Total Resistance The total series resistance is the sum of all four resistors: $R_{\text{total}} = 5\,\Omega + 10\,\Omega + 5\,\Omega + 10\,\Omega = 30\,\Omega$. Step 4: Apply Ohm’s Law to Find the Current The supply voltage is 9 V. Applying Ohm’s law ($I = \frac{V}{R}$) gives: $i = \frac{9\,\text{V}}{30\,\Omega} = 0.3\,\text{A}.$ Step 5: State the Final Answer The current in the network is therefore 0.3 A.

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