Two identical capacitors A and B, charged to the same potential 5V are connected in two different circuits as shown below at time t = 0. If the charge on capacitors A and B at time t = CR is QA and QB respectively, then (Here e is the base of natural logarithm)

Question

Two identical capacitors A and B, charged to the same potential 5V are connected in two different circuits as shown below at time t = 0. If the charge on capacitors A and B at time t = CR is Q_A and Q_B respectively, then (Here e is the base of natural logarithm)

Q_A = ${{CV} \over e}$, Q_B = ${{VC} \over 2}$

Q_A = ${{CV} \over 2}$, Q_B = ${{VC} \over e}$

Q_A = VC, Q_B = ${{VC} \over e}$

Q_A = VC, Q_B = CV

Solution

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