The integral $\int {{{dx} \over {{{(x + 4)}^{{8 \over 7}}}{{(x - 3)}^{{6 \over 7}}}}}} $ is equal to : (where C is a constant of integration)

Question

The integral $\int {{{dx} \over {{{(x + 4)}^{{8 \over 7}}}{{(x - 3)}^{{6 \over 7}}}}}} $ is equal to :
(where C is a constant of integration)

${1 \over 2}{\left( {{{x - 3} \over {x + 4}}} \right)^{{3 \over 7}}} + C$

${\left( {{{x - 3} \over {x + 4}}} \right)^{{1 \over 7}}} + C$

$ - {1 \over {13}}{\left( {{{x - 3} \over {x + 4}}} \right)^{{{13} \over 7}}} + C$

-${\left( {{{x - 3} \over {x + 4}}} \right)^{-{1 \over 7}}} + C$

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