A vessel of depth 2h is half filled with a liquid of refractive index $2\sqrt 2 $ and the upper half with another liquid of refractive index $\sqrt 2 $ . The liquids are immiscible. The apparent depth of the inner surface of the bottom of vessel will be :

Question

${h \over {\sqrt 2 }}$

${h \over {3\sqrt 2 }}$

${3 \over 4}h\sqrt 2 $

${h \over {2\left( {\sqrt 2 + 1} \right)}}$

Solution

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