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Question

As shown in figure, when a spherical cavity (centered at O) of radius 1 is cut out of a uniform sphere of radius R (centered at C), the centre of mass of remaining (shaded) part of sphere is at G, i.e, on the surface of the cavity. R can be detemined by the equation :

(R2 + R – 1) (2 – R) = 1
(R2 – R – 1) (2 – R) = 1
(R2 – R + 1) (2 – R) = 1
(R2 + R + 1) (2 – R) = 1

Solution

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