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Question
If a, b and c are the greatest value of 19Cp, 20Cq and 21Cr respectively, then :
${a \over {11}} = {b \over {22}} = {c \over {21}}$
${a \over {10}} = {b \over {22}} = {c \over {21}}$
${a \over {10}} = {b \over {11}} = {c \over {42}}$
${a \over {11}} = {b \over {22}} = {c \over {42}}$

Solution

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