The inverse function of f(x) = ${{{8^{2x}} - {8^{ - 2x}}} \over {{8^{2x}} + {8^{ - 2x}}}}$, x $ \in $ (-1, 1), is :

Question

The inverse function of

f(x) = ${{{8^{2x}} - {8^{ - 2x}}} \over {{8^{2x}} + {8^{ - 2x}}}}$, x $ \in $ (-1, 1), is :

${1 \over 4}{\log _e}\left( {{{1 - x} \over {1 + x}}} \right)$

${1 \over 4}\left( {{{\log }_8}e} \right){\log _e}\left( {{{1 - x} \over {1 + x}}} \right)$

${1 \over 4}\left( {{{\log }_8}e} \right){\log _e}\left( {{{1 + x} \over {1 - x}}} \right)$

${1 \over 4}{\log _e}\left( {{{1 + x} \over {1 - x}}} \right)$

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