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Question
When photon of energy 4.0 eV strikes the surface of a metal A, the ejected photoelectrons have maximum kinetic energy TA eV end de-Broglie wavelength $\lambda _A$. The maximum kinetic energy of photoelectrons liberated from another metal B by photon of energy 4.50 eV is TB = (TA – 1.5) eV. If the de-Broglie wavelength of these photoelectrons $\lambda _B$ = 2$\lambda _A$, then the work function of metal B is :
1.5eV
4eV
2eV
3eV

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