Question
When photon of energy 4.0 eV strikes the
surface of a metal A, the ejected photoelectrons
have maximum kinetic energy TA eV end
de-Broglie wavelength $\lambda _A$. The maximum
kinetic energy of photoelectrons liberated from
another metal B by photon of energy 4.50 eV
is TB = (TA – 1.5) eV. If the de-Broglie
wavelength of these photoelectrons $\lambda _B$ = 2$\lambda _A$,
then the work function of metal B is :