An electron (of mass m) and a photon have the same energy E in the range of a few eV. The ratio of the de-Broglie wavelength associated with the electron and the wavelength of the photon is (c = speed of light in vaccuum)

Question

${1 \over c}{\left( {{{2E} \over m}} \right)^{{1 \over 2}}}$

${1 \over c}{\left( {{E \over {2m}}} \right)^{{1 \over 2}}}$

${\left( {{E \over {2m}}} \right)^{{1 \over 2}}}$

$c{\left( {2mE} \right)^{{1 \over 2}}}$

Solution

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